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2011 - Final Value of Variable After Performing Operations

🇬🇧 Inglizcha: There is a programming language with only four operations and one variable X:

  • ++X and X++ increments the value of the variable X by 1.
  • --X and X-- decrements the value of the variable X by 1.

Initially, the value of X is 0.

Given an array of strings operations containing a list of operations, return the final value of X after performing all the operations.

🇺🇿 O'zbekcha: Bitta dasturlash tili bor 4 ta operatsiya bilan va X o'zgaruvchisi bor:

  • ++X va X++ operatsiyasilari X o'zgaruvchini 1 ga oshiradi.
  • --X va X-- operatsiyasilari X o'zgaruvchini 1 ga kamaytiradi.

X ning boshlang'ich qiymati 0.

Berilgan operations array barcha bajarilishi bo'lgan operatsiya(string)larni o'z ichiga olgan. Barcha operatsiyadan so'ng X ning yakuniy qiymati qaytarilsin.

🟢 Misol 1

$ Input: operations = ["--X","X++","X++"]
$ Output: 1
$ Explanation: The operations are performed as follows:
Initially, X = 0.
--X: X is decremented by 1, X =  0 - 1 = -1.
X++: X is incremented by 1, X = -1 + 1 =  0.
X++: X is incremented by 1, X =  0 + 1 =  1.

🟢 Misol 2

$ Input: operations = ["++X","++X","X++"]
$ Output: 3
$ Explanation: The operations are performed as follows:
Initially, X = 0.
++X: X is incremented by 1, X = 0 + 1 = 1.
++X: X is incremented by 1, X = 1 + 1 = 2.
X++: X is incremented by 1, X = 2 + 1 = 3.

🟢 Misol 3

$ Input: operations = ["X++","++X","--X","X--"]
$ Output: 0
$ Explanation: The operations are performed as follows:
Initially, X = 0.
X++: X is incremented by 1, X = 0 + 1 = 1.
++X: X is incremented by 1, X = 1 + 1 = 2.
--X: X is decremented by 1, X = 2 - 1 = 1.
X--: X is decremented by 1, X = 1 - 1 = 0.

🔴 Cheklovlar

  • 1 <= operations.length <= 100
  • operations[i] will be either "++X", "X++", "--X", or "X--".

1⃣ - Yechim: LINK

Bitta x o'zgaruvchisini ochib olamiz va operations ni har bitta elementi "++" yoki "--" o'z ichiga olishini tekshirib shu bo'yicha kerakli amallarni bajaramiz.

⏰ Time Complexity: O(n)
📦 Space Complexity: O(1)

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# Author: Abdulaminkhon Khaydarov
# Date: 06/11/22 
# Problem URL: https://leetcode.com/problems/final-value-of-variable-after-performing-operations/

from typing import List


class Solution:
    def finalValueAfterOperations(self, operations: List[str]) -> int:
        x = 0

        for operation in operations:
            if "++" in operation:
                x += 1
            else:
                x -= 1

        return x


if __name__ == '__main__':
    solution = Solution()

    # Example 1
    print(solution.finalValueAfterOperations(["--X", "X++", "X++"]) == 1)

    # Example 2
    print(solution.finalValueAfterOperations(["++X", "++X", "X++"]) == 3)

    # Example 3
    print(solution.finalValueAfterOperations(["X++", "++X", "--X", "X--"]) == 0)
Oxirgi yangilanish: November 13, 2022 09:15:23